Thursday, August 30, 2012

Handbook of Formulae and Physical Constants

For The Use Of Students And Examination Candidates
Approved by the Interprovincial Power Engineering Curriculum Committee and the Provincial Chief Inspectors' Association's Committee for the standardization of Power Engineer's Examinations n Canada.
Duplication of this material for student in-class use or for examination purposes is permitted without written approval.
www.powerengineering.ca
Printed July 2003

Table of Contents
TOPIC PAGE
SI Multiples..........................................................................................1
Basic Units (distance, area, volume, mass, density)............................2
Mathematical Formulae.......................................................................5
Applied Mechanics.............................................................................10
Thermodynamics.................................................................................21
Fluid Mechanics..................................................................................28
Electricity............................................................................................30
Periodic Table.....................................................................................34
Names in the Metric System
VALUE
EXPONENT
SYMBOL
PREFIX
1 000 000 000 000
1012
T
tera
1 000 000 000
109
G
giga
1 000 000
106
M
mega
1 000
103
k
kilo
100
102
h
hecto
10
101
da
deca
0.1
10-1
d
deci
0.01
10-2
c
centi
0.001
10-3
m
milli
0.000 001
10-6
μ
micro
0.000 000 001
10-9
n
nano
0.000 000 000 001
10-12
p
pico
Conversion Chart for Metric Units
To
Milli-
To
Centi-
To
Deci-
To
Metre,
Gram,
Litre
To
Deca-
To
Hecto-
To
Kilo-
Kilo-
x 106
x 105
x 104
x 103
x 102
x 101
To Convert
Hecto-
x 105
x 104
x 103
x 102
x 101
x 10-1
Deca-
x 104
x 103
x 102
x 101
x 10-1
x 10-2
Metre,
Gram,
Litre
x 103
x 102
x 101
x 10-1
x 10-2
x 10-3
Deci-
x 102
x 101
x 10-1
x 10-2
x 10-3
x 10-4
Centi-
x 101
x 10-1
x 10-2
x 10-3
x 10-4
x 10-5
Milli-
x 10-1
x 10-2
x 10-3
x 10-4
x 10-5
x 10-6
Page 1
BASIC UNITS
SI IMPERIAL
DISTANCE
1 metre (1 m) = 10 decimetres (10 dm) 12 in. = 1 ft
= 100 centimetres (100 cm) 3 ft = 1 yd
= 1000 millimetres (1000 mm) 5280 ft = 1 mile
1760 yd = 1 mile
1 decametre (1 dam) = 10 m
1 hectometre (1 hm) = 100 m
1 kilometre (1 km) = 1000 m
Conversions:
1 in. = 25.4 mm
1 ft = 30.48 cm
1 mile = 1.61 km
1 yd = 0.914 m
1 m = 3.28 ft
Area
1 sq metre (1 m2) = 10 000 cm2 1 ft2 = 144 in.2
= 1 000 000 mm2 1 yd2 = 9 ft2
1 sq mile = 640 acre = 1 section
1 sq hectometre (1 hm2) = 10 000 m2
= 1 hectare (1 ha)
1 sq km (1 km2) = 1 000 000 m2
Conversions:
1 in.2 = 6.45 cm2 = 645 mm2
1 m2 = 10.8 ft2
1 acre = 0.405 ha
1 sq mile = 2.59 km2 Page 2
SI IMPERIAL
Volume
1 m3 = 1 000 000 cm3 1 ft3 = 1728 in.3
= 1 x 109 mm3 1 yd3 = 27 ft3
1 dm3 = 1 litre 1(liquid) U.S. gallon = 231 in.3
1 litre = 1000 cm3 = 4 (liquid) quarts
1 mL = 1 cm3 1 U.S. barrel (bbl) = 42 U.S. gal.
1 m3 = 1000 litres 1 imperial gallon = 1.2 U.S. gal.
Conversions:
1 in.3 = 16.4 cm3
1 m3 = 35.3 ft3
1 litre = 61 in.3
1 U.S.gal = 3.78 litres
1 U.S. bbl = 159 litres
1 litre/s = 15.9 U.S. gal/min
Mass and Weight
1 kilogram (1 kg) = 1000 grams 2000 lb = 1 ton (short)
1000 kg = 1 tonne 1 long ton = 2240 lb
Conversions:
1 kg (on Earth) results in a weight of 2.2 lb
Density
volumemass density mass= volumeweight densityweight =
⎟⎠⎞⎜⎝⎛=3mkg Vm ρ ⎟⎠⎞⎜⎝⎛=3ftlb Vw ρ
Conversions:
(onEarth)amassdensityof1kgm3resultsinaweightdensityof0.0623lbft3 Page 3
SI Imperial
RELATIVE DENSITY
In SI R.D. is a comparison of mass density In Imperial the corresponding quantity is
to a standard. For solids and liquids the specific gravity; for solids and liquids a
standard is fresh water. comparison of weight density to that of water.
Conversions:
In both systems the same numbers
hold for R.D. as for S.G. since
these are equivalent ratios.
RELATIVE DENSITY (SPECIFIC GRAVITY) OF VARIOUS SUBSTANCES
Water (fresh)...............1.00 Mica............................2.9
Water (sea average)....1.03 Nickel.........................8.6
Aluminum...................2.56 Oil (linseed)................0.94
Antimony....................6.70 Oil (olive)...................0.92
Bismuth.......................9.80 Oil (petroleum)...........0.76-0.86
Brass...........................8.40 Oil (turpentine)...........0.87
Brick...........................2.1 Paraffin.......................0.86
Calcium.......................1.58 Platinum....................21.5
Carbon (diamond).......3.4 Sand (dry)...................1.42
Carbon (graphite)........2.3 Silicon.........................2.6
Carbon (charcoal).......1.8 Silver.........................10.57
Chromium...................6.5 Slate............................2.1-2.8
Clay.............................1.9 Sodium........................0.97
Coal.............................1.36-1.4 Steel (mild).................7.87
Cobalt.........................8.6 Sulphur.......................2.07
Copper........................8.77 Tin...............................7.3
Cork............................0.24 Tungsten...................19.1
Glass (crown)..............2.5 Wood (ash).................0.75
Glass (flint).................3.5 Wood (beech).............0.7-0.8
Gold..........................19.3 Wood (ebony).............1.1-1.2
Iron (cast)....................7.21 Wood (elm).................0.66
Iron (wrought)............7.78 Wood (lignum-vitae)..1.3
Lead..........................11.4 Wood (oak).................0.7-1.0
Magnesium.................1.74 Wood (pine)................0.56
Manganese..................8.0 Wood (teak)................0.8
Mercury....................13.6 Zinc.............................7.0
Page 4
Greek Alphabet
Alpha α Iota ι Rho ρ
Beta β Kappa κ Sigma Σ, σ
Gamma γ Lambda λ Tau τ
Delta Δ Mu μ Upsilon υ
Epsilon ε Nu ν Phi Φ, φ
Zeta ζ Xi ξ Kai χ
Eta η Omicron Ο Psi ψ
Theta θ Pi π Omega Ω, ω
MATHEMATICAL FORMULAE
Algebra
1. Expansion Formulae
(x + y)2 = x2 + 2xy + y2
(x - y)2 = x2 - 2xy + y2
x2 - y2 = (x - y) (x + y)
(x + y)3 = x3 + 3x2y + 3xy2 + y3
x3 + y3 = (x + y) (x2 - xy + y2)
(x - y)3 = x3 - 3x2y + 3xy2 - y3
x3 - y3 = (x - y) (x2 + xy + y2)
2. Quadratic Equation
If ax2 + bx + c = 0,
Then x = 2aac4b b-2−± Page 5
Trigonometry
1. Basic Ratios
hy A Sin =, hx A cos=, xy A tan =
2. Pythagoras' Law
x2 + y2 = h2
3. Trigonometric Function Values
Sin is positive from 0° to 90° and positive from 90° to 180°
Cos is positive from 0° to 90° and negative from 90° to 180°
Tan is positive from 0° to 90° and negative from 90° to 180°
4. Solution of Triangles
a. Sine Law
CSin cBSin bA Sin a==
b. Cosine Law
c2 = a2 + b2 - 2 ab Cos C
a2 = b2 + c2 - 2 bc Cos A
b2 = a2 + c2 - 2 ac Cos B
Page 6
Geometry
1. Areas of Triangles
a. All Triangles
2heightlar perpendicu x base Area=
Area 2BSin ac 2CSin ab2ASin bc ===
and,
c) - (s b) - (s a)-(s s Area=
where, s is half the sum of the sides, or s = 2c b a++
b. Equilateral Triangles
Area = 0.433 x side2
2. Circumference of a Circle
C = πd
3. Area of a Circle
A = πr2 = 2r x ncecircumfere = 2d4π = 0.7854d2
4. Area of a Sector of a Circle
A = 2r x arc
A = 2r x π360θ° (θ = angle in degrees)
A = 2rθ2° (θ = angle in radians)
Page 7
5. Area of a Segment of a Circle
A = area of sector – area of triangle
Also approximate area = 0.608-hd h 342
6. Ellipse
A = Dd4π
Approx. circumference = ()2d D π+
7. Area of Trapezoid
A = h 2b a⎟⎠⎞⎜⎝⎛+
8. Area of Hexagon
A = 2.6s2 where s is the length of one side
9. Area of Octagon
A = 4.83s2 where s is the length of one side
10. Sphere
Total surface area A =4πr2
Surface area of segment As = πdh
Volume V = 3r π34
Volume of segment
Vs=πh23(3r–h)Vs=πh6(h2+3a2)wherea=radiusofsegmentbase
Page 8
11. Volume of a Cylinder
V = Ld4π2 where L is cylinder length
12. Pyramid
Volume
V = 31 base area x perpendicular height
Volume of frustum
VF = )Aa a (A 3h++ where h is the perpendicular height, A and a are areas as shown
13. Cone
Area of curved surface of cone:
A = 2DL π
Area of curved surface of frustum
AF = 2d)L (D π+
Volume of cone:
V=basearea×perpendicularheight3
Volume of frustum:
VF=perpendicularheight×π(R2+r2+Rr)3
Page 9
APPLIED MECHANICS
Scalar - a property described by a magnitude only
Vector - a property described by a magnitude and a direction
Velocity - vector property equal to displacementtime
The magnitude of velocity may be referred to as speed
In SI the basic unit is ms, in Imperial fts
Other common units are kmh,mih
Conversions: sft 3.28 sm 1=
hmi 0.621 hkm 1=
Speed of sound in dry air is 331 ms at 0°C and increases by about 0.61 ms for each °C rise
Speed of light in vacuum equals 3 x 108 ms
Acceleration - vector property equal to changeinvelocitytime
In SI the basic unit is 2sm, in Imperial 2sft
Conversion: 12sm = 3.28 2sft
Acceleration due to gravity, symbol "g", is 9.81 2sm or 32.2 2sft
Page 10
LINEAR VELOCITY AND ACCELERATION
u initial velocity
v final velocity
t elapsed time
s displacement
a acceleration
v=u+ats=v+u2ts=ut+12at2v2=u2+2as
Angular Velocity and Acceleration
θ angular displacement (radians)
ω angular velocity (radians/s); ω1 = initial, ω2 = final
α angular acceleration (radians/s2)
ω2 = ω1 + α t
θ = ω1 + ω2 x t
2
θ = ω1 t + ½ α t2
ω22 = ω12 + 2 α θ
linear displacement, s = r θ
linear velocity, v = r ω
linear, or tangential acceleration, aT = r α
Page 11
Tangential, Centripetal and Total Acceleration
Tangential acceleration aT is due to angular acceleration α
aT=rα
Centripetal (Centrifugal) acceleration ac is due to change in direction only
ac = v2/r = r ω2
Total acceleration, a, of a rotating point experiencing angular acceleration is the vector sum
of aT and ac
a = aT + ac
FORCE
Vector quantity, a push or pull which changes the shape and/or motion of an object
In SI the unit of force is the newton, N, defined as a kgms2
In Imperial the unit of force is the pound lb
Conversion: 9.81 N = 2.2 lb
Weight
The gravitational force of attraction between a mass, m, and the mass of the Earth
In SI weight can be calculated from
Weight = F = mg , where g = 9.81 m/s2
In Imperial, the mass of an object (rarely used), in slugs, can be calculated from the known weight in pounds
m=Weightgg=32.2fts2
Page 12
Newton's Second Law of Motion
An unbalanced force F will cause an object of mass m to accelerate a, according to:
F = ma (Imperial F = wg a, where w is weight)
Torque Equation
T = I α where T is the acceleration torque in Nm, I is the moment of inertia in kg m2 and α is the angular acceleration in radians/s2
Momentum
Vector quantity, symbol p,
p = mv (Imperial p = wg v, where w is weight)
in SI unit is kgms
Work
Scalar quantity, equal to the (vector) product of a force and the displacement of an object. In simple systems, where W is work, F force and s distance
W = Fs
In SI the unit of work is the joule, J, or kilojoule, kJ
1 J = 1 Nm
In Imperial the unit of work is the ft-lb
Energy
Energy is the ability to do work, the units are the same as for work; J, kJ, and ft-lb
Page 13
Kinetic Energy
Energy due to motion
Ek=12mv2
In Imperial this is usually expressed as Ek=w2gv2 where w is weight
Kinetic Energy of Rotation
22Rωmk21 E= where k is radius of gyration, ω is angular velocity in rad/s
or
2RIω21 E= where I = mk2 is the moment of inertia
CENTRIPETAL (CENTRIFUGAL) FORCE
rmv F2C= where r is the radius
or
FC = m ω2 r where ω is angular velocity in rad/s
Potential Energy
Energy due to position in a force field, such as gravity
Ep = m g h
In Imperial this is usually expressed Ep = w h where w is weight, and h is height above some specified datum
Page 14
Thermal Energy
In SI the common units of thermal energy are J, and kJ, (and kJ/kg for specific quantities)
In Imperial, the units of thermal energy are British Thermal Units (Btu)
Conversions: 1 Btu = 1055 J
1 Btu = 778 ft-lb
Electrical Energy
In SI the units of electrical energy are J, kJ and kilowatt hours kWh. In Imperial, the unit of electrical energy is the kWh
Conversions: 1 kWh = 3600 kJ
1 kWh = 3412 Btu = 2.66 x 106 ft-lb
Power
A scalar quantity, equal to the rate of doing work
In SI the unit is the Watt W (or kW)
1W=1Js
In Imperial, the units are:
Mechanical Power - ft–lbs, horsepower h.p.
Thermal Power - Btus
Electrical Power - W, kW, or h.p.
Conversions: 746 W = 1 h.p.
1 h.p. = 550 ft–lbs
1 kW = 0.948 Btus
Page 15
Pressure
A vector quantity, force per unit area
In SI the basic units of pressure are pascals Pa and kPa
1Pa=1Nm2
In Imperial, the basic unit is the pound per square inch, psi
Atmospheric Pressure
At sea level atmospheric pressure equals 101.3 kPa or 14.7 psi
Pressure Conversions
1 psi = 6.895 kPa
Pressure may be expressed in standard units, or in units of static fluid head, in both SI and Imperial systems
Common equivalencies are:
1 kPa = 0.294 in. mercury = 7.5 mm mercury
1 kPa = 4.02 in. water = 102 mm water
1 psi = 2.03 in. mercury = 51.7 mm mercury
1 psi = 27.7 in. water = 703 mm water
1 m H2O = 9.81 kPa
Other pressure unit conversions:
1 bar = 14.5 psi = 100 kPa
1 kg/cm2 = 98.1 kPa = 14.2 psi = 0.981 bar
1 atmosphere (atm) = 101.3 kPa = 14.7 psi
Page 16
Simple Harmonic Motion
Velocity of P = sm x- R ω22
Acceleration of P = ω2 x m/s2
The period or time of a complete oscillation = ωπ2 seconds
General formula for the period of S.H.M.
T = 2πonacceleratintdisplaceme
Simple Pendulum
T = 2π gL T = period or time in seconds for a double swing
L = length in metres
The Conical Pendulum
R/H = tan θ= Fc/W = ω2 R/g
Page 17
Lifting Machines
W = load lifted, F = force applied
M.A. = effortload = FW
V.R. (velocity ratio) = distance loaddistanceeffort
η = efficiency = V.R.M.A.
1. Lifting Blocks
V.R. = number of rope strands supporting the load block
2. Wheel & Differential Axle
Velocity ratio = 2)r -(r π2Rπ21
= 1r -r 2R2 R
Or, using diameters instead of radii,
Velocity ratio = )d - (d2D1
3. Inclined Plane
V.R. = heightlength
4. Screw Jack
V.R. = threadofpitch leverage of ncecircumfere Page 18
Indicated Power
I.P. = Pm A L N where I.P. is power in W, Pm is mean or "average" effective pressure in Pa, A is piston area in m2, L is length of stroke in m and N is number of power strokes per second
Brake Power
B.P. = Tω where B.P. is brake power in W, T is torque in Nm and ω is angular velocity in radian/second
STRESS, STRAIN and MODULUS OF ELASTICITY
Direct stress = APareaload=
Direct strain = L length originalextension􀁁Δ=
Modulus of elasticity
E = 􀁁􀁁Δ=Δ=APLL/P/Astraindirect stressdirect
Shear stress τ = shearunder areaforce
Shear strain = Lx
Modulus of rigidity
G = strainshear stressshear Page 19
General Torsion Equation (Shafts of circular cross-section)
TJ=τr=GθL
)d (d32π )r - (r 2π J32πdr2π J 4241424144−==== Shaft HollowFor 2. Shaft SolidFor 1.
T = torque or twisting moment in newton metres
J = polar second moment of area of cross-section about shaft axis.
τ = shear stress at outer fibres in pascals
r = radius of shaft in metres
G = modulus of rigidity in pascals
θ = angle of twist in radians
L = length of shaft in metres
d = diameter of shaft in metres
Relationship Between Bending Stress and External Bending Moment
MI=σy=ER
1. For Rectangle
M = external bending moment in newton metres
I = second moment of area in m4
σ = bending stress at outer fibres in pascals
y = distance from centroid to outer fibres in metres
E = modulus of elasticity in pascals
R = radius of currative in metres
I = 12BD3
2. For Solid Shaft
I=πD464
Page 20
THERMODYNAMICS
Temperature Scales
°)32F (95 C−°= °F = 32 C 59+°
°R = °F + 460 (R Rankine) K = °C + 273 (K Kelvin)
Sensible Heat Equation
Q = mcΔT
m is mass
c is specific heat
ΔT is temperature change
Latent Heat
Latent heat of fusion of ice = 335 kJ/kg
Latent heat of steam from and at 100°C = 2257 kJ/kg
1 tonne of refrigeration = 335 000 kJ/day
= 233 kJ/min
Gas Laws
1. Boyle’s Law
When gas temperature is constant
PV = constant or
P1V1 = P2V2
where P is absolute pressure and V is volume
2. Charles’ Law
When gas pressure is constant, constant TV=
or V1T1=V2T2 , where V is volume and T is absolute temperature
Page 21
3. Gay-Lussac's Law
When gas volume is constant, constantTP=
Or 2211TPTP= , where P is absolute pressure and T is absolute temperature
4. General Gas Law
P1V1T1=P2V2T2=constant
P V = m R T where P = absolute pressure (kPa)
V = volume (m3)
T = absolute temp (K)
m = mass (kg)
R = characteristic constant (kJ/kgK)
Also
PV = nRoT where P = absolute pressure (kPa)
V = volume (m3)
T = absolute temperature K
N = the number of kmoles of gas
Ro = the universal gas constant 8.314 kJ/kmol/K
SPECIFIC HEATS OF GASES
Specific Heat at Specific Heat at Ratio of Specific
Constant Pressure Constant Volume Heats
kJ/kgK kJ/kgK γ = cp / cv
GAS or or
kJ/kg oC kJ/kg oC
Air 1.005 0.718 1.40
Ammonia 2.060 1.561 1.32
Carbon Dioxide 0.825 0.630 1.31
Carbon Monoxide 1.051 0.751 1.40
Helium 5.234 3.153 1.66
Hydrogen 14.235 10.096 1.41
Hydrogen Sulphide 1.105 0.85 1.30
Methane 2.177 1.675 1.30
Nitrogen 1.043 0.745 1.40
Oxygen 0.913 0.652 1.40
Sulphur Dioxide 0.632 0.451 1.40
Page 22
Efficiency of Heat Engines
Carnot Cycle η=T1–T2T1 where T1 and T2 are absolute temperatures of heat source and sink
Air Standard Efficiencies
1. Spark Ignition Gas and Oil Engines (Constant Volume Cycle or Otto Cycle)
1) - (γvr1 - 1 η= where rv = compression ratio = volumeclearanceolumecylinder v
γ = volume)(constant heat specificpressure)(constant heat specific
2. Diesel Cycle
)1 - γ(R r)1(R - 1 η1 - γvγ−= where r = ratio of compression
R = ratio of cut-off volume to clearance volume
3. High Speed Diesel (Dual-Combustion) Cycle
[]1) - k(βγ 1) -(k r1 - kβ - 1 η1 - γvγ+=
where rv = volumeclearanceolumecylinder v
k = combustion Vconstant of beginningat pressue absoluten)(combustio heating Vconstant of endat pressue absolute
β = volumeclearancen)(combustio heating Pconstant of endat volume
4. Gas Turbines (Constant Pressure or Brayton Cycle)
⎟⎟⎠⎞⎜⎜⎝⎛−=γ1γpr1 - 1 η
Page 23
where rp = pressure ratio = pressure intake compressorpressure discharge compressor
Page 24
Heat Transfer by Conduction
Q=λAtΔTdwhereQ=heattransferredinjoulesλ=thermalconductivityorcoeficientofheattransferinJ×mm2×s×°CorWm×°CA=areainm2t=timeinsecondsΔT=temperaturedifferencebetweensurfacesin°Cd=thicknessoflayerinm
COEFFICIENTS OF THERMAL CONDUCTIVITY
Material
Coefficient of
Thermal Conductivity
W/m °C
Air
Aluminum
Brass
Brick
Concrete
Copper
Cork
Felt
Glass
Glass, fibre
Iron, cast
Plastic, cellular
Steel
Wood
Wallboard, paper
0.025
206
104
0.6
0.85
380
0.043
0.038
1.0
0.04
70
0.04
60
0.15
0.076
Page 25
Thermal Expansion of Solids
Increase in length = L α (T2 – T1 )
where L = original length
α = coefficient of linear expansion
(T2 – T1 ) = rise in temperature
Increase in volume = V β (T2 – T1 )
Where V = original volume
β = coefficient of volumetric expansion
(T2 – T1 ) = rise in temperature
coefficient of volumetric expansion = coefficient of linear expansion x 3
β = 3α
Page 26
Chemical Heating Value of a Fuel
Chemical Heating Value MJ per kg of fuel = 22O33.7 C + 144 H - + 9.3 S8()
C is the mass of carbon per kg of fuel
H2 is the mass of hydrogen per kg of fuel
O2 is the mass of oxygen per kg of fuel
S is the mass of sulphur per kg of fuel
Theoretical Air Required to Burn Fuel
Air (kg per kg of fuel) = 228O100C + 8 H - + S 38[()]23
Air Supplied from Analysis of Flue Gases
Air in kg per kg of fuel = N233(CO2+CO)×C
C is the percentage of carbon in fuel by mass
N2 is the percentage of nitrogen in flue gas by volume
CO2 is the percentage of carbon dioxide in flue gas by volume
CO is the percentage of carbon monoxide in flue gas by volume
Boiler Formulae
Equivalent evaporation = kJ/kg 2257)h - (h m21s􀀅
Factor of evaporation = kJ/kg 2257)h - (h 21
Boiler efficiency = fuel of valuecalorific x m)h - (h mf21s􀀅􀀅
where = mass flow rate of steam sm􀀅
h1 = enthalpy of steam produced in boiler
h2 = enthalpy of feedwater to boiler
= mass flow rate of fuelfm􀀅
Page 27
FLUID MECHANICS
Discharge from an Orifice
Let A = cross-sectional area of the orifice = (π/4)d2
and Ac = cross-sectional area of the jet at the vena conrtacta = ((π/4)2cd
then Ac = CcA
or Cc = 2ccddAA⎟⎠⎞⎜⎝⎛=
where Cc is the coefficient of contraction
At the vena contracta, the volumetric flow rate Q of the fluid is given by
Q=areaofthejetatthevenacontracta×actualvelocity=AcvorQ=CcACv2gh
The coefficients of contraction and velocity are combined to give the coefficient of discharge, Cd
i.e.Cd=CcCvandQ=CdA2gh
Typically, values for Cd vary between 0.6 and 0.65
Circular orifice: Q = 0.62 A 2gh
Where Q = flow (m3/s) A = area (m2) h = head (m)
Rectangular notch: Q = 0.62 (B x H) 232gh
Where B = breadth (m) H = head (m above sill)
Triangular Right Angled Notch: Q = 2.635 H5/2
Where H = head (m above sill)
Page 28
Bernoulli’s Theory
H = 2gvwP h 2++
H = total head (metres) w = force of gravity on 1 m3 of fluid (N)
h = height above datum level (metres) v = velocity of water (metres per second)
P = pressure (N/m2 or Pa)
Loss of Head in Pipes Due to Friction
Loss of head in metres = fLdv22g
L = length in metres v = velocity of flow in metres per second
d = diameter in metres f = constant value of 0.01 in large pipes to 0.02 in small pipes
Note: This equation is expressed in some textbooks as
Loss = 4fLdv22g where the f values range from 0.0025 to 0.005
Actual Pipe Dimensions
Page 29
ELECTRICITY
Ohm's Law
I = RE
or E = IR
where I = current (amperes)
E = electromotive force (volts)
R = resistance (ohms)
Conductor Resistivity
R = ρaL
where ρ = specific resistance (or resistivity) (ohm metres, Ω·m)
L = length (metres)
a = area of cross-section (square metres)
Temperature correction
Rt = Ro (1 + αt)
where Ro = resistance at 0ºC (Ω)
Rt = resistance at tºC (Ω)
α = temperature coefficient which has an average value for copper of 0.004 28 (Ω/ΩºC)
R2 = R1)αt (1)αt (112++
where R1 = resistance at t1 (Ω)
R2 = resistance at t2 (Ω)
α Values Ω/ΩºC
copper 0.00428
platinum 0.00385
nickel 0.00672
tungsten 0.0045
aluminum 0.0040
Page 30
Dynamo Formulae
Average e.m.f. generated in each conductor = 2ΦNpZ60c
where Z = total number of armature conductors
c = number of parallel paths through winding between positive and negative brushes where c = 2 (wave winding), c = 2p (lap winding)
Φ = useful flux per pole (webers), entering or leaving the armature
p = number of pairs of poles
N = speed (revolutions per minute)
Generator Terminal volts = EG – IaRa
Motor Terminal volts = EB + IaRa
where EG = generated e.m.f.
EB = generated back e.m.f.
Ia = armature current
Ra = armature resistance
Alternating Current
R.M.S. value of sine curve = 0.707 maximum value
Mean value of sine curve = 0.637 maximum value
Form factor of sinusoidal = 11.10.6370.707 Mean value valueR.M.S.==
Frequency of alternator = 60pN cycles per second
Where p = number of pairs of poles
N = rotational speed in r/min
Page 31
Slip of Induction Motor
100 x field of Speedrotor of speed - field of speed Slip
Inductive Reactance
Reactance of AC circuit (X) = 2πfL ohms
where L = inductance of circuit (henries)
Inductance of an iron cored solenoid = henries10x LμAT256.182
where T = turns on coil
μ = magnetic permeablility of core
A = area of core (square centimetres)
L = length (centimetres)
Capacitance Reactance
Capacitance reactance of AC circuit = πfC21ohms
where C = capacitance (farads)
Total reactance = ohmsfC 2π1- πfL2⎟⎠⎞⎜⎝⎛
Impedence (Z) = 22reactance)(e)(resistanc+
= ohms )fC π21 - fL (2π R22+
Current in AC Circuit
impedance voltsimpressed Current =
Page 32
Power Factor
p.f. = amperes x volts wattstrue
also p.f. = cos Φ, where Φ is the angle of lag or lead
Three Phase Alternators
Star connected
Line voltage = 3 x phase voltage
Line current = phase current
Delta connected
Line voltage = phase voltage
Line current = 3 x phase current
Three phase power
P = 3 EL IL cos Φ
EL = line voltage
IL = line current
cos Φ = power factor
Page 33
Page 34
ION NAMES AND FORMULAE
MONATOMIC POLYATOMIC
Ag+ silver ion BO33- borate ion
Al3+ aluminum ion C2H3O2- acetate ion
Au+ and Au2+ gold ion ClO- hypochlorite ion
Be2+ beryllium ion ClO2- chlorite ion
Ca2+ calcium ion ClO3- chlorate ion
Co2+ and Co3+ cobalt ion ClO4- perchlorate ion
Cr2+ and Cr3+ chromium ion CN- cyanide ion
Cu+ and Cu2+ copper ion CO32- carbonate ion
Fe2+ and Fe3+ iron ion C2O42- oxalate ion
K+ potassium ion CrO42- chromate ion
Li+ lithium ion Cr2O72- dichromate ion
Mg2+ magnesium ion HCO3- hydrogen carbonate or bicarbonate ion
Na+ sodium ion H3O+ hydronium ion
Zn2+ zinc ion HPO42- hydrogen phosphate ion
H2PO4- dihydrogen phosphate ion
HSO3- hydrogen sulphite or bisulphite ion
HSO4- hydrogen sulphate or bisulphate ion
MnO4- permanganate ion
N3- azide ion
NH4+ ammonium ion
NO2- nitrite ion
NO3- nitrate ion
O22- peroxide ion
OCN- cyanate ion
OH- hydroxide ion
PO33- phosphite ion
PO43- phosphate ion
SCN- thiocyanate ion
SO32- sulphite ion
SO42- sulphate ion
S2O32- thiosulphate ion
Page 35




This material is owned by Power Engineering Training Systems and may not be modified from its original form. Duplication of this material for student use in-class or for examination purposes is permitted without written approval.
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Education budget should increase five-fold: Leena Mehendale


Former Maharashtra additional chief secretary Leena Mehendale has said that Indian Education system requires major reforms. She pitched for increasing the budgetary allocation for the sector five-fold.
"Bring in reforms in education, increase budget five-folds and give many-fold increase to the budget of vocational education," she said.
Speaking on the importance of vocational education, she said, “Emphasis should be given on the use of TV for cost-reduction of vocational education and private TV channels should be asked to use 10 per cent of their time on this.”
"The 'atrocious system' of examination should be revamped and made user-friendly and a suitable certification and equivalence system between non-formal and formal education should be created," she said.
"The government should strictly implement the Unnikrishnan judgement on capitation fee of Supreme Court even at school level to stop the menace of capitation fee in schools," Mehendale said.
"Private institutions sought and got the status of Deemed University and unilaterally started acting as if the judgement does not apply to them. The government has connived at them. They should be brought under the fold once again," she said.
The government should stop supporting costly schools by land-grant, tax-exemptions, recognition and instead give premium for education in mother-tongue, she said.
[Source: Indian Express]

ઇલેક્ટ્રિક સાધનોનો બોડીગાર્ડ ફ્યૂ


સાયન્સ ટોક
બાળમિત્રો, તમારી ટોળકીમાં કોઈ ફ્રેન્ડ થાકી ગયા હોય કે ઉદાસ હોય તો તમે એને ખીજવતા હો છો ને કે ‘આનો તો ફ્યૂઝ જ ઊડી ગયો લાગે છે!’ અથવા તો ઘરમાં લાઇટ જાય ત્યારે પણ પહેલું કારણ જે સામે આવે છે તે કયું આવે છે? તો એ હોય છે ફયૂઝ ઊડી જવાનું.તમને ક્યારેય થાય છે ખરું કે યાર આ ફ્યૂઝ ઊડી જવો એ કઇ બલા છે? તો આજે સરસ રીતે સમજી લો કે આ ઇલેક્ટ્રિક ફ્યૂઝ કઇ કરામત છે વીજળીનો ફ્યૂઝ એવું સાધન છે જેમાં આવતા કરંટનું દબાણ વધી જતા તે ઇલેક્ટ્રિક સર્કીટને તોડી નાખે છે. કરંટ ક્યાં તો અતિશય વધી જાય અથવા તો ઓછો થઈ જાય ત્યારે ફ્યુઝ ઊડી જતો હોય છે. ઇલેક્ટ્રિક ફ્યૂઝ તારનો એવો ટુકડો હોય છે જે ઓગળવાની ક્ષમતા ઘણી ઓછી હોય છે. સામાન્ય રીતે તે ટીન અને લેડની મિશ્ર ધાતુમાંથી બનાવવામાં આવે છે. ફ્યૂઝનો તાર હોલ્ડરમાં લગાવવામાં આવે છે. ફ્યૂઝ હોલ્ડર પોર્સીલેન કે એબોનાઇટમાંથી બનાવાય છે.
ફ્યૂઝ કેવી રીતે કામ કરે છે તેનું કુતૂહલ થતું હોય તો જાણી લો કે, કોઈ પણ ઇલેક્ટ્રિક સર્કીટમાં ફ્યૂઝ એક સુરક્ષાના સાધન તરીકે કામ કરે છે. જ્યારે કરંટ ર્સિકટની વચ્ચેથી પસાર થાય ત્યારે કરંટનું પ્રમાણ વધી જાય તો ફ્યૂઝ ઓગળીને ર્સિકટને તોડી નાંખે છે. એટલે તે અસરકારક રીતે ઘરનાં ઇલેક્ટ્રિક ઉપકરણોને નુકસાનથી બચાવી લે છે. શોર્ટ ર્સિકટ ત્યારે થાય છે જ્યારે બે તાર ભેગા થઈ જાય છે. બે તાર ભેગા થવાથી વધારે પ્રમાણમાં કરંટ પસાર થવા લાગે તો આગ પણ લાગી શકે છે. જ્યારે કોઈ સિંગલ ર્સિકટમાં વધારેપડતા ઇલેક્ટ્રિક ઉપકરણ લગાવી દેવામાં આવે ત્યારે આવું ખાસ થાય છે.
પ્લગ ફ્યૂઝ તથા કાર્ટરિજ ફ્યૂઝ- એમ બે પ્રકારના ફ્યૂઝ હોય છે. પ્લગ ફ્યૂઝને સોકેટમાં સ્ક્રૂથી લગાવવામાં આવે છે. આ ફ્યૂઝનો ઉપયોગ મોટા ભાગે ઘરમાં થતો હોય છે. કાર્ટરિજ ફ્યૂઝને સ્પ્રિંગ લોડેડ બ્રેકેટ્સમાં લગાવવામાં આવે છે. કોઈ પણ ફ્યૂઝમાંથી પસાર થતો ઊંચો સુરક્ષિત કરંટ ફ્યૂઝ રેટિંગ કહેવાય છે. આ રેટિંગ કેટલાક મિલી એમ્પિયરથી માંડીને ૫૦ એમ્પિયર સુધીનો કે તેથી વધારેનો હોઈ શકે છે. ઓછા રેટિંગવાળા ફ્યૂઝ પાતળા તારના બનેલા હોય છે જ્યારે હાઇ રેટિંગવાળા ફ્યૂઝ જાડા તાર કે પટ્ટીઓના બને છે.
હા, કોઈ પણ ફયૂઝનું રેટિંગ તેની લંબાઇ પરથી નક્કી નથી થતું, પરંતુ તેના તારની જાડાઈ પર જ નિર્ભર હોય છે. એટલે ફ્યૂઝ લગાવતી વખતે ધ્યાન રાખવું કે ક્યારેય નીચી રેટિંગવાળી ર્સિકટમાં હાઈ રેટિંગવાળો ફ્યૂઝ ન લગાવવો જોઈએ, તે ખૂબ નુકસાનકારક સાબિત થાય છે. તેના લીધે ર્સિકટમાં ઘણો વીજપ્રવાહ આવી જાય છે જે વીજ ઉપકરણને બાળી નાંખે છે કે અન્ય કોઈ નુકસાન પહોંચાડે છે. ફ્યૂઝને એ રીતે સેટ કરવામાં આવ્યો હોય છે કે તેનું જોડાણ ઉપકરણો વાપરવાનાં છે તેની સાથે કરવામાં આવેલું હોય છે. જો એનું રેટિંગ ઓછું હશે તો સ્વિચ પાડતા વીજપ્રવાહ તો વહેવા માંડશે, પરંતુ વીજપ્રવાહનું પ્રમાણ વધી જતા ફ્યૂઝ ગરમ થઈને પીગળી જશે અને ર્સિકટ તૂટી જશે. પળવારમાં બનતી આ સમગ્ર ઘટનાને આપણે ફ્યૂઝ ઊડી ગયો એમ કહીએ છીએ.  

Computer Science (CS) & IT Papers and Syllabus


Computer Science (CS) & IT Papers and Syllabus

e-books-Water Proofing

ALL INDIA LIST OF MICR CODES OF BANK BRANCHES UNDER THE JURISDICTION OF MICR-CPCs - POSITION


"There is nothing either good or bad,but thinking makes it so."



"You should not be having any REGRET FOR NOT DOING something, at the same time you should not be having GUILT FOR DOING something"

An eye for an eye only ends up making the whole world blind 

Databases Illuminated


 JONES AND  BARTLETT INDIA PVT.  LTD 
NEW ARRIVAL


Databases Illuminated, 2/e 
  Catherine Ricardo 

9789380853321   PB    2011   688pp
  
Single Colour (With Figures & Tables)  6.75x 9” 

Original Price: US$132.95 
        Special Indian Price: Rs. 595.00
Buy Online & Get 10% Discount

   


Description: This updated Second Edition of the popular Databases Illuminated integrates database theory with a practical approach to database design and implementation. The text is specifically designed for the modern database student, who will be expected to know both theory and applied design and implementation as a professional in the field. It covers conceptual material thoroughly, and then shows how concepts are applied to create working databases that illustrate the theory. Students are guided through the stages of database planning and design, beginning with requirements gathering and progressing to conceptual, logical, and physical design. This Second Edition has been revised and updated to incorporate information about the new releases of Microsoft® Access® 2010, Oracle® Database 11g, and InterSystems Cache®. It includes material on the most recent topics, such as web access, JDBC, web programming, XML, data mining, and other emerging database technologies and applications.
The integrated, modern approach to databases, combined with strong pedagogical features, accessible writing, and a full package of student and instructor resources, make Databases Illuminated, Second Edition the perfect textbook for courses in this exciting field.
New and Key Features of the Updated Second Edition:
  Provides balanced coverage of theory and applied database design and implementation throughout
•  Covers the new features of the current versions of popular database management systems, including Oracle 11g, Access 2010, and InterSystems Cache
•  Incorporates the new curriculum recommendations in ACM Computer Science Curriculum 2008 and ACM/AIS IS 2010 Curriculum Guidelines for IS 2010.2, Data and Information Management, including more attention to security, concurrency, and net-centric computing. The chapter on computer ethics has been updated to take into account new regulations and practices
• Concepts are presented and then applied in examples and in the continuing student projects and lab exercises on the website, so students receive hands-on practice with applications
•  Includes the extensive object-relational features of the current release of Oracle, with downloadable code for students to implement
•  Object-oriented databases are implemented using InterSystems Cache, with downloadable code included on the website
Contents:
Chapter 1. Introductory Database Concepts • Chapter Objectives • Uses of Databases • A Sample Database • The Integrated Database Environment • Roles in the Integrated Database Environment • Advantages of the Integrated Database Approach • Historical Developments in Information Systems • Chapter Summary • Exercises
Chapter 2. Database Planning and Database Architecture • Chapter Objectives • Data as a Resource • Characteristics of Data • Data and Information • Levels of Discussing Data • Data Sublanguages • Stages in Database Design • Design Tools • Data Dictionary • Project Management Software • Database Administration • Planning and Design • Developing the Database • Database Management • The Three-Level Database Architecture • External Views • Logical and Conceptual Models • Internal Model • Data Independence • Overview of Data Models • The Entity-Relationship Model • Relational Model • Object-Oriented Model • Object-Relational Model • Semistructured Data Model • Chapter Summary • Exercises
Chapter 3. The Entity-Relationship Model • Chapter Objectives • Purpose of the E-R Model • Entities • Attributes • Domains • Null Values • Multivalued Attributes • Composite Attributes • Derived Attributes • Keys • Superkeys • Candidate Keys • Primary Keys • Relationships • Degree of Relationships • Attributes of Relationship Sets • Cardinality of a Relationship • Showing Cardinalities on an E-R Diagram • Participation Constraints • Roles • Existence Dependency and Weak Entities • A Sample E-R Diagram • Chapter Summary • Exercises
Chapter 4. The Relational Model • Chapter Objectives • Advantages of the Relational Model • Relational Data Structures • Tables • Mathematical Relations • Database Relations and Tables • Properties of Relations • Degree and Cardinality • Relation Keys • Integrity Constraints: domain, key, foreign key, general constraints • Representing Relational Database Schemas • Relational Data Manipulation Languages • Categories of DMLs • Relational Algebra • Views • Mapping an E-R Model to a Relational Schema • Chapter Summary • Exercises
Chapter 5. Relational Database Management Systems and SQL • Chapter Objectives • Brief History of SQL in Relational Database Systems • Architecture of a Relational Database Management System • Defining the Database: SQL DDL • CREATE TABLE • CREATE INDEX • ALTER TABLE, RENAME TABLE • DROP Statements • Manipulating the Database: SQL DML • Introduction to the SELECT Statement • SELECT Using Multiple Tables • SELECT with Other Operators • Operators for Updating: UPDATE, INSERT, DELETE • Creating and Using Views • Active Databases • Enabling and Disabling Constraints • SQL Triggers • Using COMMIT and ROLLBACK Statements • SQL Programming • SQL PSMs • Embedded SQL • Dynamic SQL • APls • The System Catalog • Chapter Summary • Exercises
Chapter 6. Normalization • Chapter Objectives • Objectives of Normalization • Insertion, Update, and Deletion Anomalies • Functional Dependency • Superkeys, Candidate Keys, and Primary Keys • Normalization Using Primary Keys • First Normal Form • Full Functional Dependency and Second Normal Form • Transitive Dependency and Third Normal Form • Boyce-Codd Normal Form • Comprehensive Example of Functional Dependencies • Properties of Relational Decompositions • Attribute Preservation • Dependency Preservation • Lossless Decomposition • Decomposition Algorithm for Boyce-Codd Normal Form with • Lossless Join • The Normalization Process • Analysis • Synthesis • Normalization from an Entity-Relationship Diagram • When to Stop Normalizing • Chapter Summary • Exercises
Chapter 7. The Object-Oriented Model • Chapter Objectives • Rationale for the Object-Oriented Data Model • Object-Oriented Data Concepts • Objects and Literals • Classes • Class Hierarchies and Inheritance • Object Identity • Object-Oriented Data Modeling Using UML • The ODMG Model and ODL • Class Declarations • Extent • Attributes • Relationships • Methods • Classes and Inheritance • N-ary Relationships and M:N Relationships with Attributes • Keys • Object Query Language • Developing an 00 Database • Developing an 00 Database in Cache • Chapter Summary • Exercises
Chapter 8. The Enhanced Entity-Relationship Model and the Object-Relational Model • Chapter Objectives • Rationale for Extending the E-R Model • Generalization and Specialization • Specialization • Generalization • Generalization Constraints-Disjointness, Completeness, Definition • Method • Multiple Hierarchies and Inheritance • Union • Using (min,max) Notation for Cardinality and Participation • A Sample EE-R Diagram • Mapping the EE-R Model to a Relational Model • Summary of E-R to Strictly Relational Mapping Concepts • Mapping EE-R Class Hierarchies to Relational Tables • Mapping Unions • Extending the Relational Model • New Fundamental Data Types • Collection Types • User-Defined Data Types (UDT) • Reference Types • Type Hierarchies in Standard SQL • Type Hierarchies in Oracle • Nested Tables in Oracle • Oracle Object Views • Converting an EE-R Diagram to an Object-Relational Database Model • Chapter Summary • Exercises
Chapter 9. Introduction to Database Security • Chapter Objectives • Issues in Database Security • Accidental Security Threats • Deliberate Security Threats • Physical Security and User Authentication • Authorization • Access Control • Using Views for Access Control • Security Logs and Audit Trails • Encryption • SQL Authorization Language • Security in Oracle • The Oracle Enterprise Manager Database Control Facility • Security Control Using SQL *Plus • Object Privileges • System Privileges • Roles • Statistical Database Security • Database Security and the Internet • Proxy Servers • Firewalls • Digital Signatures • Certification Authorities • Chapter Summary • Exercises
Chapter 10. Transaction Management • Chapter Objectives • Properties of Transactions • Need for Concurrency Control • Serializability • Locking • Deadlock • Two-Phase Locking Protocol • Levels of Locking •  Timestamping • Basic Timestamping Protocol • Thomas’ Write Rule • Multiversion Timestamping • Optimistic Techniques • Need for Recovery • Recovery Techniques • Deferred Update Protocol • Checkpoints • Immediate Update Protocol • Shadow Paging • Overview of ARIES Recovery Algorithm • Transaction Management in Oracle • Chapter Summary • Exercises
Chapter 11. Relational Query Optimization • Chapter Objectives • Query Processing and Query Optimization • Algebraic Techniques for Query Transformation • The Query Tree • An SQL Query and Its Relational Algebra Translation • Performing SELECT Operations Early • Evaluating Conjunctive Conditions • Performing PROJECT Early • Equivalence of Algebraic Operations • Heuristics for Query Optimization • Processing Techniques and Cost Estimation • Cost Factors • Cost of Processing Selects • Processing Joins • Processing Other Operations • Pipelining • Query Optimization in Oracle • Chapter Summary • Exercises
Chapter 12. Distributed Databases • Chapter Objectives • Rationale for Distribution • Architectures for a Distributed Systems • Distributed Processing Using a Centralized Database • Client-Server Systems • Parallel Databases • Distributed Databases • Components of a Distributed Database System • Data Placement • Transparency • Transaction Control for Distributed Databases • Concurrency Control • Recovery • Distributed Query Processing • Steps in Distributed Query Processing • Estimating Data Communications Costs • The Semijoin Operation • Chapter Summary • Exercises
Chapter 13. Databases and the Internet • Chapter Objectives • Introduction • Fundamental Concepts of the Internet and the World Wide Web • Origins of the World Wide Web • Browsers, Links, and URIs • HTTP • HTML • XML • Tiered Architectures • Single-Tier Architecture • Two-Tier Architecture • Three-Tier Architecture • Web Programming with Oracle • PL/SQL Web Toolkit • PL/SQL Server Pages (PSP) • JDBC • The Semi-Structured Data Model • Graphical Representation • XML Parsers • XML Data Manipulation • XML and Relational Databases • XML in Oracle • XML DB • Oracle XML Developer’s Kits • Chapter Summary • Exercises
Chapter 14. Social and Ethical Issues • Chapter Objectives • Computerization and Society • Ethical Issues • Ethical Standards for Computing Professionals • Intellectual Property • Definition of Intellectual Property • Legal Protections for Intellectual Property • Intellectual Property Protection for Software • Databases and Privacy Issues • Privacy and Security • Privacy as a Human Right • Human Factors • Human Factors in Software Development • The Human-Database Interface • Usability Testing for Database Applications • Chapter Summary • Exercises
Chapter 15. Data Warehouses and Data Mining • Chapter Objectives • Origins of Data Warehouses • Operational Databases and Data Warehouses • Architecture of a Data Warehouse • Developing a Data Warehouse • Top-Down Method • Bottom-Up Method • Comparison of Methods • Data Models for Data Warehouses • ROLAP and MOLAP • Data Cubes and Hypercubes • Star Schema • Snowflake Schema • Columnar Data • Data Warehouse Queries and SQL • Aggregate Functions • RANK Functions • CUBE and ROLLUP Functions • Analytic Functions • Optimization and Index Techniques • Views and View Materialization • Data Warehouse Vendors • Data Mining • Purpose of Data Mining • Types of Knowledge Discovered • Models and Methods Used • Data Mining Process Model • Regression • Decision Trees • Artificial Neural Networks • Clustering • Genetic Algorithms • Applications of Data Mining • Retailing • Banking and Finance • Manufacturing • Science and Medicine • Homeland Security • Search Engines • Data Mining Software Providers • Chapter Summary • Exercises • Index
About the Author:
Catherine M. Ricardo, PhD-Iona College
Catherine Ricardo received a Ph.D. from Columbia University in 1983. She has been on the Computer Science faculty at Iona College since 1979. She has taught a variety of courses including computer literacy, introductory programming in several languages, data structures, discrete mathematics, educational computing, modeling, and artificial intelligence, but she has concentrated on courses in database systems, which she has taught at both the undergraduate and graduate level for over 25 years. Besides writing textbooks on databases, she has written numerous articles and made presentations at many conferences in the field.
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Special Series: Bollywood's hottest seniors!


Last updated on:
September 5, 2011 18:40 IST

Rekha
Hindi filmdom is all about great style and elegance, at all ages. There's little wonder then, that these filmi veteran heroines may have aged considerably but they are far from jaded.
In our special series, we've seen the sensational 20-somethings, the saucy 30-somethings and the hot 40-somethings. Now, let's give it up for the seniors of the film industry.
Rekha

Rekha -- the ultimate diva -- is showing no signs or desire of giving up the greasepaint and the works at 56. Not that we are complaining.

It's a wonder though, that she manages to look way younger than her years.

 

 

 

 

 

 

 

 

Dimple Kapadia

Last updated on: September 5, 2011 18:40 IST
Dimple Kapadia
In two more years, it will be 40 years since Dimple's debut film Bobby released. Her other most memorable film, Saagar came out in the late 1980s but fans and admirers still remember how she sizzled on screen.

She was breathtaking as the single middle-aged woman in Dil Chahta Hai opposite Akshaye Khanna. That's 54-year-old Dimple Kapadia for you.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Rati Agnihotri

Last updated on: September 5, 2011 18:40 IST
Rati Agnihotri
The lovely Rati Agnihotri is back in films and we are loving it! The 50-year-old actress, who charmed us in Ek Duje Ke Liye is one of the most elegant actresses of her time.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Zeenat Aman

Last updated on: September 5, 2011 18:40 IST
Zeenat Aman
Bollywood's original poster-girl stilll exudes the oomph that catapulted her to stardom back in the 1970s. That's why she's still walking the ramp at 59.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Hema Malini

Last updated on: September 5, 2011 18:40 IST
Hema Malini
Hema Malini is 62 but hardly looks it. The Dream Girl keeps getting better with age.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Sharmila Tagore

Last updated on: September 5, 2011 18:40 IST
Sharmila Tagore
The regal-looking Sharmila Tagore is 64 and mother to the dishy Saif Ali Khan and Soha. She's also one of the most accomplished actresses of her time.

 

 

 

 

 

 

 

 

 

 

 

 

 

Asha Parekh

Last updated on: September 5, 2011 18:40 IST
Asha Parekh
At 68, Asha Parekh is still as poised and pretty.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Saira Banu

Last updated on: September 5, 2011 18:40 IST
Saira Banu
Saira Banu glows like few people do at 67. But then that could be the reason of being married to Dilip Kumar, who still holds her hand in public.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Tanuja

Last updated on: September 5, 2011 18:40 IST
Tanuja
At 67, Tanuja sometimes upstages her daughters -- Kajol and Tanisha -- with her lovely appearances.

 

 

 

 

 

 

 

 

 

 

 

 

Simi Garewal

Last updated on: September 5, 2011 18:40 IST
Simi Garewal
Remember this? This fine specimen of a woman just seems to have reversed time to her advantage and at 63, quite a looker.

 

 

 

 

 

 

 

 

 

 

 

 

 

Vyjayantimala

Last updated on: September 5, 2011 18:40 IST
Vyjayantimala
Vyjayantimala may be 75, but she's still got the fierceness of a young dancer. What a livewire!

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Waheeda Rehman

Last updated on: September 5, 2011 18:40 IST
Waheeda Rehman
Waheeda Rehman is, by far, the most elegant woman at 75 we'll ever see. Now that's a class apart.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Sadhana

Last updated on: September 5, 2011 18:40 IST
Sadhana
Sadhana, who recently celebrated her 70th birthday recently, is known as India's Audrey Hepburn. Enough said.